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$y(t)=\sum_{n=0}^{\infty}\dfrac{(-1)^nt^{2n}}{n!}$

$y(t)=\sum_{n=0}^{\infty}\dfrac{t^{2n}}{2^nn!}$

$\mbox{None of the above}$

$y(t)=\sum_{n=0}^{\infty}\dfrac{(-1)^nt^{3n}}{3^n}$

$y(t)=\sum_{n=0}^{\infty}\dfrac{(-1)^nt^{3n}}{3^nn!}$

$y(t)=\sum_{n=0}^{\infty}\dfrac{t^{3n}}{3^nn!}$

$y(t)=\sum_{n=0}^{\infty}\dfrac{(-1)^nt^{2n}}{2^nn!}$

Test:	DELA-Section 2.8-Series solutions-Hard
Number of Questions:	12
Time:

	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{4^n(2 \cdot 4 \cdot 6 \ldots 2n)}{1 \cdot 3 \cdot 5 \ldots (2n-1)}x^{2n}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{4^n(1 \cdot 3 \cdot 5 \ldots (2n-1))}{2 \cdot 4 \cdot 6 \ldots 2n}x^{2n}$
	$\mbox{None of the above}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{2^n(1 \cdot 3 \cdot 5 \ldots (2n-1))}{2 \cdot 4 \cdot 6 \ldots 2n}x^{2n}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{2^n(2 \cdot 4 \cdot 6 \ldots 2n)}{1 \cdot 3 \cdot 5 \ldots (2n-1)}x^{2n}$

	$y(x)=c_1\left [1+\sum_{n=1}^{\infty}\dfrac{(-2)^{n}}{1\cdot 3\cdot 5\ldots (2n-1)}x^{2n}\right ]+c_2\left [\sum_{n=0}^{\infty}\dfrac{(-1)^{n}}{n!}x^{2n+1}\right ]$
	$y(x)=c_1\left [\sum_{n=0}^{\infty}\dfrac{(-1)^{n}}{1\cdot 3\cdot 5\ldots (2n+1)}x^{2n+1}\right ]+c_2\left [\sum_{n=0}^{\infty}\dfrac{(-2)^{n}}{n!}x^{2n}\right ]$
	$\mbox{None of the above}$
	$y(x)=c_1\left [1+\sum_{n=1}^{\infty}\dfrac{(-1)^{n}}{1\cdot 3\cdot 5\ldots (2n-1)}x^{2n}\right ]+c_2\left [\sum_{n=0}^{\infty}\dfrac{(-2)^{n}}{n!}x^{2n}\right ]$
	$y(x)=c_1\left [\sum_{n=0}^{\infty}\dfrac{(-2)^{n}}{1\cdot 3\cdot 5\ldots (2n+1)}x^{2n+1}\right ]+c_2\left [\sum_{n=0}^{\infty}\dfrac{(-1)^{n}}{n!}x^{2n+1}\right ]$

Test!

	$y=1+\sum_{n=1}^{\infty}\dfrac{x^{3n+1}}{1\cdot 4\ldots (3n-2)}$
	$y=1+\sum_{n=1}^{\infty}\dfrac{x^{3n}}{1\cdot 4\ldots (3n-2)}$
	$y=1+\sum_{n=1}^{\infty}\dfrac{x^{3n+1}}{2\cdot 5\ldots (3n-1)}$
	$\mbox{None of the above}$
	$y=1+\sum_{n=1}^{\infty}\dfrac{x^{3n}}{2\cdot 5\ldots (3n-1)}$

	$y=1+\sum_{n=1}^{\infty}\dfrac{(-1)^{n}1\cdot 3\cdot 5\ldots (2n+1)}{(2n)!}x^{2n+1}$
	$y=1+\sum_{n=1}^{\infty}\dfrac{(-1)^{n}2\cdot 4\cdot 6\ldots (2n)}{(2n+1)!}x^{2n+1}$
	$y=1+\sum_{n=1}^{\infty}\dfrac{(-1)^{n}1\cdot 3\cdot 5\ldots (2n+1)}{(2n)!}x^{2n}$
	$y=1+\sum_{n=1}^{\infty}\dfrac{(-1)^{n}2\cdot 4\cdot 6\ldots (2n)}{(2n+1)!}x^{2n}$
	$\mbox{None of the above}$

	$y(x)=\sum_{n=0}^{\infty}\dfrac{1}{1\cdot 4\cdot 7\ldots (3n+1)}x^{3n}$
	$y(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^n}{1\cdot 4\cdot 7\ldots (3n+1)}x^{3n+1}$
	$y(x)=\sum_{n=0}^{\infty}\dfrac{1}{1\cdot 4\cdot 7\ldots (3n+1)}x^{3n+1}$
	$y(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^{n+1}}{1\cdot 4\cdot 7\ldots (3n+1)}x^{3n+1}$
	$\mbox{None of the above}$

	$\mbox{None of the above}$
	$y=c_1\left (1+\sum_{n=1}^{\infty}\dfrac{1\cdot 3\cdot 5\ldots (2n-1)}{2^n \cdot 2\cdot 4\ldots (2n)}x^{2n}\right )+c_2\left (x+\sum_{n=1}^{\infty}\dfrac{2\cdot 4\cdot 6\ldots (2n)}{2^n \cdot 1\cdot 3\cdot 5\ldots (2n+1)}x^{2n+1}\right )$
	$y=c_1\left (1+\sum_{n=1}^{\infty}\dfrac{1\cdot 3\cdot 5\ldots (2n-1)}{2^n \cdot 2\cdot 4\ldots (2n)}x^{2n+1}\right )+c_2\left (x+\sum_{n=1}^{\infty}\dfrac{2\cdot 4\cdot 6\ldots (2n)}{2^n \cdot 1\cdot 3\cdot 5\ldots (2n+1)}x^{2n}\right )$
	$y=c_1\left (1+\sum_{n=1}^{\infty}\dfrac{1\cdot 3\cdot 5\ldots (2n-1)}{4^n \cdot 2\cdot 4\ldots (2n)}x^{2n+1}\right )+c_2\left (x+\sum_{n=1}^{\infty}\dfrac{2\cdot 4\cdot 6\ldots (2n)}{4^n \cdot 1\cdot 3\cdot 5\ldots (2n+1)}x^{2n}\right )$
	$y=c_1\left (1+\sum_{n=1}^{\infty}\dfrac{1\cdot 3\cdot 5\ldots (2n-1)}{4^n \cdot 2\cdot 4\ldots (2n)}x^{2n}\right )+c_2\left (x+\sum_{n=1}^{\infty}\dfrac{2\cdot 4\cdot 6\ldots (2n)}{4^n \cdot 1\cdot 3\cdot 5\ldots (2n+1)}x^{2n+1}\right )$

	$\mbox{None of the above}$
	$y=c_1\sum_{n=0}^{\infty}(-1)^n(n+1)x^{2n+1}+c_2\sum_{n=0}^{\infty}(-1)^n(2n+3)x^{2n}$
	$y=c_1\dsum_{n=0}^{\infty}(n+1)x^{2n}+c_2\sum_{n=0}^{\infty}(2n+3)x^{2n+1}$
	$y=c_1\sum_{n=0}^{\infty}(n+1)x^{2n+1}+c_2\dsum_{n=0}^{\infty}(2n+3)x^{2n}$
	$y=c_1\sum_{n=0}^{\infty}(-1)^n(n+1)x^{2n}+c_2\sum_{n=0}^{\infty}(-1)^n(2n+3)x^{2n+1}$

	$y=c_1\sum_{n=0}^{\infty}\dfrac{(-1)^n}{(2n)!}x^{2n}+c_2\sum_{n=0}^{\infty}\dfrac{(-1)^n}{(2n+1)!}x^{2n+1}$
	$y=c_1\sum_{n=0}^{\infty}\dfrac{1}{(2n)!}x^{2n}+c_2\sum_{n=0}^{\infty}\dfrac{1}{(2n+1)!}x^{2n+1}$
	$y=c_1\sum_{n=0}^{\infty}\dfrac{(-1)^n}{(2n)!}x^{2n}+c_2\sum_{n=0}^{\infty}\dfrac{1}{(2n+1)!}x^{2n+1}$
	$y=c_1\sum_{n=0}^{\infty}\dfrac{1}{(2n)!}x^{2n}+c_2\sum_{n=0}^{\infty}\dfrac{(-1)^n}{(2n+1)!}x^{2n+1}$
	$\mbox{None of the above}$

	$y=c_1\sum_{n=0}^{\infty}(-1)^nx^{2n}+c_2\sum_{n=0}^{\infty}(-1)^nx^{2n+1}$
	$y=c_1\sum_{n=0}^{\infty}(-1)^n\dfrac{x^{2n}}{(2n)2^n}+c_2\sum_{n=0}^{\infty}(-1)^n\dfrac{x^{2n+1}}{(2n+1)2^{n+1}}$
	$y=c_1\sum_{n=0}^{\infty}(-1)^n\dfrac{x^{2n}}{(2n)!}+c_2\sum_{n=0}^{\infty}(-1)^n\dfrac{x^{2n+1}}{(2n+1)!}$
	$y=c_1\sum_{n=0}^{\infty}(-1)^n\dfrac{x^{2n}}{(2n)!}+c_2\sum_{n=0}^{\infty}(-1)^{n+1}\dfrac{x^{2n+1}}{(2n+1)!}$
	$\mbox{None of the above}$