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$y(x)=\sum_{n=0}^{\infty}\dfrac{x^{2n}}{2\cdot 4\cdot 6\ldots (2n)}$

$\mbox{None of the above}$

$y(x)=\sum_{n=0}^{\infty}\dfrac{x^{2n+1}}{1\cdot 3\cdot 5\ldots (2n+1)}$

$y(x)=\sum_{n=0}^{\infty}(-1)^{n}\dfrac{x^{2n+1}}{1\cdot 3\cdot 5\ldots (2n+1)}$

$y(x)=\sum_{n=0}^{\infty}(-1)^{n}\dfrac{x^{2n}}{2\cdot 4\cdot 6\ldots (2n)}$

Test:	DELA-Section 2.8-Series solutions-Average
Number of Questions:	3
Time:

	$\mbox{None of the above}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{2^{n+1}}{1\cdot 3\cdot 5\ldots (2n-1)}x^{2n}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{2^{n}}{2\cdot 4\cdot 6\ldots (2n)}x^{2n}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{2^{n}}{1\cdot 3\cdot 5\ldots (2n-1)}x^{2n}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{2^{n}}{1\cdot 3\cdot 5\ldots (2n-1)}x^{2n+1}$

	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{x^{2n}}{2\cdot 4\cdot 6\ldots (2n)}$
	$y(x)=1+\sum_{n=1}^{\infty}(-1)^{n}\dfrac{x^{2n}}{2\cdot 4\cdot 6\ldots (2n)}$
	$y(x)=1+\sum_{n=1}^{\infty}\dfrac{x^{2n+1}}{2\cdot 4\cdot 6\ldots (2n)}$
	$y(x)=1+\sum_{n=1}^{\infty}(-1)^{n}\dfrac{x^{2n+1}}{2\cdot 4\cdot 6\ldots (2n)}$
	$\mbox{None of the above}$

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